JEE Main 201910 Apr, Evening shiftMathematicsEasyMatrices and Determinants245× since 2002The sum of the real roots of the equation ∣x−6−12−3xx−3−32xx+2∣=0\left| {\matrix{ x & { - 6} & { - 1} \cr 2 & { - 3x} & {x - 3} \cr { - 3} & {2x} & {x + 2} \cr } } \right| = 0x2−3−6−3x2x−1x−3x+2=0, is equal to :AOption A. - 4BOption B. 0COption C. 1DOption D. 6CheckSkip · show solution
