JEE Main 20249 Apr, Evening shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002The sum of the coefficient of x2/3x^{2 / 3}x2/3 and x−2/5x^{-2 / 5}x−2/5 in the binomial expansion of (x2/3+12x−2/5)9\left(x^{2 / 3}+\frac{1}{2} x^{-2 / 5}\right)^9(x2/3+21x−2/5)9 isAOption A. 19/4BOption B. 69/16COption C. 63/16DOption D. 21/4CheckSkip · show solution