JEE Main 20231 Feb, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002The sum of the absolute maximum and minimum values of the function f(x)=∣x2−5x+6∣−3x+2f(x)=\left|x^{2}-5 x+6\right|-3 x+2f(x)=x2−5x+6−3x+2 in the interval [−1,3][-1,3][−1,3] is equal to :AOption A. 13BOption B. 24COption C. 10DOption D. 12CheckSkip · show solution