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JEE Main 2024 Integral Calculus Question with Answer (1 Feb Evening shift, Q31) | JEE Arc

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JEE Arc/Mathematics/Integral Calculus

Integral Calculus: JEE Main 2024 Mathematics question

JEE Main 2024 · 1 Feb, Evening shift · Q31

JEE Main 20241 Feb, Evening shiftMathematicsMediumIntegral Calculus369× since 2002

The sum of squares of all possible values of

k

, for which area of the region bounded by the parabolas

2 y^2=\mathrm{k} x

and

\mathrm{ky}^2=2(y-x)

is maximum, is equal to :

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2024 · 1 Feb, Evening shift · Q31

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