JEE Main 202623 Jan, Evening shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002The sum of all the real solutions of the equation log(x+3)(6x2+28x+30)=5−2log(6x+10)(x2+6x+9)\log_{(x+3)}\left(6x^2+28x+30\right)=5-2\log_{(6x+10)}\left(x^2+6x+9\right)log(x+3)(6x2+28x+30)=5−2log(6x+10)(x2+6x+9) is equal toAOption A. 4BOption B. 2COption C. 1DOption D. 0CheckSkip · show solution
