JEE Main 2016Session, Shift 1MathematicsMediumComplex Numbers and Quadratic Equations264× since 2002The sum of all real values of xxx satisfying the equation (x2−5x+5)x2+4x−60 =1{\left( {{x^2} - 5x + 5} \right)^{{x^2} + 4x - 60}}\, = 1(x2−5x+5)x2+4x−60=1 is :AOption A. 666BOption B. 555COption C. 333DOption D. −4-4−4CheckSkip · show solution