JEE Main 202226 Jul, Morning shiftMathematicsHardMathematical Reasoning115× since 2008The statement (∼(p⇔ ∼q))∧q(\sim(\mathrm{p} \Leftrightarrow \,\sim \mathrm{q})) \wedge \mathrm{q}(∼(p⇔∼q))∧q is :AOption A. a tautologyBOption B. a contradictionCOption C. equivalent to (p⇒q)∧q(p \Rightarrow q) \wedge q(p⇒q)∧qDOption D. equivalent to (p⇒q)∧p(p \Rightarrow q) \wedge p(p⇒q)∧pCheckSkip · show solution
