JEE Main 20249 Apr, Morning shiftMathematicsMediumDifferential Equations163× since 2002The solution of the differential equation (x2+y2)dx−5xy dy=0,y(1)=0(x^2+y^2) \mathrm{d} x-5 x y \mathrm{~d} y=0, y(1)=0(x2+y2)dx−5xy dy=0,y(1)=0, is :AOption A. ∣x2−4y2∣5=x2\left|x^2-4 y^2\right|^5=x^2x2−4y25=x2BOption B. ∣x2−2y2∣6=x\left|x^2-2 y^2\right|^6=xx2−2y26=xCOption C. ∣x2−2y2∣5=x2\left|x^2-2 y^2\right|^5=x^2x2−2y25=x2DOption D. ∣x2−4y2∣6=x\left|x^2-4 y^2\right|^6=xx2−4y26=xCheckSkip · show solution
