JEE Main 201911 Jan, Evening shiftMathematicsMediumDifferential Equations163× since 2002The solution of the differential equation, dydx{{dy} \over {dx}}dxdy = (x – y)², when y(1) = 1, is :AOption A. −-− log_e ∣1+x−y1−x+y∣\left| {{{1 + x - y} \over {1 - x + y}}} \right|1−x+y1+x−y = x + y −-− 2BOption B. log_e ∣2−x2−y∣\left| {{{2 - x} \over {2 - y}}} \right|2−y2−x = x −-− yCOption C. log_e ∣2−y2−x∣\left| {{{2 - y} \over {2 - x}}} \right|2−x2−y = 2(y −-− 1)DOption D. −-− log_e ∣1−x+y1+x−y∣\left| {{{1 - x + y} \over {1 + x - y}}} \right|1+x−y1−x+y = 2(x −-− 1)CheckSkip · show solution
