JEE Main 2007Annual, Paper 1MathematicsMediumIntegral Calculus369× since 2002The solution for xxx of the equation ∫2xdttt2−1=π2\int\limits_{\sqrt 2 }^x {{{dt} \over {t\sqrt {{t^2} - 1} }} = {\pi \over 2}}2∫xtt2−1dt=2π isAOption A. 32{{\sqrt 3 } \over 2}23BOption B. 222\sqrt 222COption C. 222DOption D. NoneCheckSkip · show solution
