The solubility of CdSO₄ in water is 8.0 × 10⁻⁴ mol L⁻¹. Its solubility in 0.01 M H₂SO₄ solution is _ _ _ _ _ × 10⁻⁶ mol L⁻¹. (Round off to the Nearest Integer). (Assume that solubility is much less than 0.01 M)

Equilibrium: JEE Main 2021 Chemistry question

JEE Main 2021 · 18 Mar, Evening shift · Q13

JEE Main 202118 Mar, Evening shiftChemistryMediumEquilibrium123× since 2002

The solubility of CdSO₄ in water is 8.0

\times

10^

-

4 mol L^

-

1. Its solubility in 0.01 M H₂SO₄ solution is __________

\times

10^

-

6 mol L^

-

1. (Round off to the Nearest Integer). (Assume that solubility is much less than 0.01 M)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Equilibrium Question with Answer (18 Mar Evening shift, Q13) | JEE Arc