The slope of normal at any point (x, y), x > 0, y > 0 on the curve y = y(x) is given by (x²)/(xy - x²y² - 1). If the curve passes through the point (1, 1), then e. y(e) is equal to

(D) (1 + tan (1))/(1 - tan (1))

(A) (1 - tan (1))/(1 + tan (1))

Limit, Continuity and Differentiability: JEE Main 2022 Mathematics question

JEE Main 2022 · 24 Jun, Evening shift · Q2787

JEE Main 202224 Jun, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

The slope of normal at any point (x, y), x > 0, y > 0 on the curve y = y(x) is given by

{{{x^2}} \over {xy - {x^2}{y^2} - 1}}

. If the curve passes through the point (1, 1), then e . y(e) is equal to

JEE Main 2022 · 24 Jun, Evening shift · Q2787

JEE Main 202224 Jun, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002

The slope of normal at any point (x, y), x > 0, y > 0 on the curve y = y(x) is given by

{{{x^2}} \over {xy - {x^2}{y^2} - 1}}

. If the curve passes through the point (1, 1), then e . y(e) is equal to