JEE Main 2003Annual, Paper 1MathematicsEasyThree Dimensional Geometry249× since 2002The shortest distance from the plane 12x+4y+3z=32712x+4y+3z=32712x+4y+3z=327 to the sphere x2+y2+z2+4x−2y−6z=155{x^2} + {y^2} + {z^2} + 4x - 2y - 6z = 155x2+y2+z2+4x−2y−6z=155 isAOption A. 393939BOption B. 262626COption C. 1141311{4 \over {13}}11134DOption D. 131313CheckSkip · show solution
