The shortest distance between the lines x/2 = y/2 = z/1 and (x + 2)/(- 1) = (y - 4)/8 = (z - 5)/4 lies in the interval:

Three Dimensional Geometry: JEE Main 2016 Mathematics question

JEE Main 2016 · 9 Apr, Morning shift · Q2486

JEE Main 20169 Apr, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002

The shortest distance between the lines

{x \over 2} = {y \over 2} = {z \over 1}

and

{{x + 2} \over { - 1}} = {{y - 4} \over 8} = {{z - 5} \over 4}

lies in the interval :

JEE Main 2016 · 9 Apr, Morning shift · Q2486

JEE Main 20169 Apr, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002

The shortest distance between the lines

{x \over 2} = {y \over 2} = {z \over 1}

and

{{x + 2} \over { - 1}} = {{y - 4} \over 8} = {{z - 5} \over 4}

lies in the interval :