The shortest distance between the lines (x - 3)/3 = (y - 8)/(- 1) = (z - 3)/1 and (x + 3)/(- 3) = (y + 7)/2 = (z - 6)/4 is:

Three Dimensional Geometry: JEE Main 2020 Mathematics question

JEE Main 2020 · 8 Jan, Morning shift · Q2492

JEE Main 20208 Jan, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002

The shortest distance between the lines

{{x - 3} \over 3} = {{y - 8} \over { - 1}} = {{z - 3} \over 1}

and

{{x + 3} \over { - 3}} = {{y + 7} \over 2} = {{z - 6} \over 4}

is :

JEE Main 2020 · 8 Jan, Morning shift · Q2492

JEE Main 20208 Jan, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002

The shortest distance between the lines

{{x - 3} \over 3} = {{y - 8} \over { - 1}} = {{z - 3} \over 1}

and

{{x + 3} \over { - 3}} = {{y + 7} \over 2} = {{z - 6} \over 4}

is :