JEE Main 202227 Jun, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002The shortest distance between the lines x−32=y−23=z−1−1{{x - 3} \over 2} = {{y - 2} \over 3} = {{z - 1} \over { - 1}}2x−3=3y−2=−1z−1 and x+32=y−61=z−53{{x + 3} \over 2} = {{y - 6} \over 1} = {{z - 5} \over 3}2x+3=1y−6=3z−5, is :AOption A. 185{{18} \over {\sqrt 5 }}518BOption B. 2235{{22} \over {3\sqrt 5 }}3522COption C. 4635{{46} \over {3\sqrt 5 }}3546DOption D. 636\sqrt 363CheckSkip · show solution
