JEE Main 20264 Apr, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002The shortest distance between the lines r⃗=(13i^+2j^+83k^)+λ(2i^−5j^+6k^)\vec r=\left(\frac13\hat i+2\hat j+\frac83\hat k\right)+\lambda\left(2\hat i-5\hat j+6\hat k\right)r=(31i^+2j^+38k^)+λ(2i^−5j^+6k^) and r⃗=(−23i^−13k^)+μ(j^−k^)\vec r=\left(-\frac23\hat i-\frac13\hat k\right)+\mu\left(\hat j-\hat k\right)r=(−32i^−31k^)+μ(j^−k^), λ,μ∈R\lambda,\mu\in\mathbb{R}λ,μ∈R, is:AOption A. 5\sqrt55BOption B. 3COption C. 232\sqrt323DOption D. 15\sqrt{15}15CheckSkip · show solution
