The shortest distance between the lines (x-3)/2=(y+15)/(-7)=(z-9)/5 and (x+1)/2=(y-1)/1=(z-9)/(-3) is

Three Dimensional Geometry: JEE Main 2024 Mathematics question

JEE Main 2024 · 6 Apr, Morning shift · Q2542

JEE Main 20246 Apr, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002

The shortest distance between the lines

\frac{x-3}{2}=\frac{y+15}{-7}=\frac{z-9}{5}

and

\frac{x+1}{2}=\frac{y-1}{1}=\frac{z-9}{-3}

JEE Main 2024 · 6 Apr, Morning shift · Q2542

JEE Main 20246 Apr, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002

The shortest distance between the lines

\frac{x-3}{2}=\frac{y+15}{-7}=\frac{z-9}{5}

and

\frac{x+1}{2}=\frac{y-1}{1}=\frac{z-9}{-3}