JEE Main 20238 Apr, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002The shortest distance between the lines x−44=y+25=z+33\frac{x-4}{4}=\frac{y+2}{5}=\frac{z+3}{3}4x−4=5y+2=3z+3 and x−13=y−34=z−42\frac{x-1}{3}=\frac{y-3}{4}=\frac{z-4}{2}3x−1=4y−3=2z−4 is :AOption A. 363 \sqrt{6}36BOption B. 626 \sqrt{2}62COption C. 636 \sqrt{3}63DOption D. 262 \sqrt{6}26CheckSkip · show solution