JEE Main 2011Annual, Paper 1MathematicsMediumLimit, Continuity and Differentiability420× since 2002The shortest distance between line y−x=1y-x=1y−x=1 and curve x=y2x = {y^2}x=y2 isAOption A. 328{{3\sqrt 2 } \over 8}832BOption B. 832{8 \over {3\sqrt 2 }}328COption C. 43{4 \over {\sqrt 3 }}34DOption D. 34{{\sqrt 3 } \over 4}43CheckSkip · show solution