JEE Main 202127 Aug, Evening shiftMathematicsHardComplex Numbers and Quadratic Equations264× since 2002The set of all values of K > −-−1, for which the equation (3x2+4x+3)2−(k+1)(3x2+4x+3)(3x2+4x+2)+k(3x2+4x+2)2=0{(3{x^2} + 4x + 3)^2} - (k + 1)(3{x^2} + 4x + 3)(3{x^2} + 4x + 2) + k{(3{x^2} + 4x + 2)^2} = 0(3x2+4x+3)2−(k+1)(3x2+4x+3)(3x2+4x+2)+k(3x2+4x+2)2=0 has real roots, is :AOption A. (1,52]\left( {1,{5 \over 2}} \right](1,25]BOption B. [2, 3)COption C. [−12,1)\left[ { - {1 \over 2},1} \right)[−21,1)DOption D. (12,32]−{1}\left( {{1 \over 2},{3 \over 2}} \right] - \{ 1\}(21,23]−{1}CheckSkip · show solution
