The root mean square speed of molecules of a given mass of a gas at 27° C and 1 atmosphere pressure is 200 ms⁻¹. The root mean square speed of molecules of the gas at 127° C and 2 atmosphere pressure is x/(3) ms⁻¹. The value of x will be _ _ _ _ _.

Thermodynamics: JEE Main 2021 Physics question

JEE Main 2021 · 24 Feb, Evening shift · Q66

JEE Main 202124 Feb, Evening shiftPhysicsMediumThermodynamics163× since 2002

The root mean square speed of molecules of a given mass of a gas at 27

^\circ

C and 1 atmosphere pressure is 200 ms^

-

1. The root mean square speed of molecules of the gas at 127

^\circ

C and 2 atmosphere pressure is

{{x \over {\sqrt 3 }}}

ms^

-

1. The value of x will be _________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Thermodynamics Question with Answer (24 Feb Evening shift, Q66) | JEE Arc