JEE Main 202429 Jan, Morning shiftPhysicsEasyUnits and Measurements122× since 2002The resistance R=VIR=\frac{V}{I}R=IV where V=(200±5)V\mathrm{V}=(200 \pm 5) \mathrm{V}V=(200±5)V and I=(20±0.2)AI=(20 \pm 0.2) \mathrm{A}I=(20±0.2)A, the percentage error in the measurement of R\mathrm{R}R is :AOption A. 5.5%BOption B. 3%COption C. 7%DOption D. 3.5%CheckSkip · show solution
