JEE Main 202431 Jan, Morning shiftPhysicsEasyOptics190× since 2002The refractive index of a prism with apex angle AAA is cotA/2\cot A / 2cotA/2. The angle of minimum deviation is :AOption A. δm=180∘−3 A\delta_m=180^{\circ}-3 \mathrm{~A}δm=180∘−3 ABOption B. δm=180∘−4A\delta_m=180^{\circ}-4 Aδm=180∘−4ACOption C. δm=180∘−2A\delta_m=180^{\circ}-2 Aδm=180∘−2ADOption D. δm=180∘−A\delta_m=180^{\circ}-Aδm=180∘−ACheckSkip · show solution
