The rate constant for a first order reaction is given by the following equation: ln k = 33.24 - (2.0 × 10⁴ K)/T The activation energy for the reaction is given by _ _ _ _ _ _ kJ mol⁻¹. (In nearest integer) (Given: R = 8.3 J K⁻¹ mol⁻¹)

Chemical Kinetics: JEE Main 2022 Chemistry question

JEE Main 2022 · 27 Jun, Morning shift · Q4

JEE Main 202227 Jun, Morning shiftChemistryMediumChemical Kinetics62× since 2002

The rate constant for a first order reaction is given by the following equation:

\ln k = 33.24 - {{2.0 \times {{10}^4}\,K} \over T}

The activation energy for the reaction is given by ____________ kJ mol^

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1. (In nearest integer) (Given : R = 8.3 J K^

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1 mol^

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Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 Chemical Kinetics Question with Answer (27 Jun Morning shift, Q4) | JEE Arc