JEE Main 202313 Apr, Evening shiftMathematicsEasySets, Relations and Functions168× since 2002The range of f(x)=4sin−1(x2x2+1)f(x)=4 \sin ^{-1}\left(\frac{x^{2}}{x^{2}+1}\right)f(x)=4sin−1(x2+1x2) isAOption A. [0,2π][0,2 \pi][0,2π]BOption B. [0,2π)[0,2 \pi)[0,2π)COption C. [0,π)[0, \pi)[0,π)DOption D. [0,π][0, \pi][0,π]CheckSkip · show solution
