JEE Main 20265 Apr, Morning shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002The product of all possible values of α\alphaα, for which limx→0(1−cos(αx)cos((α+1)x)cos((α+2)x)sin2((α+1)x))=2\displaystyle\lim_{x\to0}\left(\frac{1-\cos(\alpha x)\cos((\alpha+1)x)\cos((\alpha+2)x)}{\sin^2((\alpha+1)x)}\right)=2x→0lim(sin2((α+1)x)1−cos(αx)cos((α+1)x)cos((α+2)x))=2, is:AOption A. −2-2−2BOption B. 1COption C. −1-1−1DOption D. 54\frac{5}{4}45CheckSkip · show solution
