The product 2^(1/4).4^(1/16).8^(1/48).16^(1/128)... to ∞ is equal to:

Sequence and Series: JEE Main 2020 Mathematics question

JEE Main 2020 · 9 Jan, Morning shift · Q5315

JEE Main 20209 Jan, Morning shiftMathematicsEasySequence and Series179× since 2002

The product

{2^{{1 \over 4}}}{.4^{{1 \over {16}}}}{.8^{{1 \over {48}}}}{.16^{{1 \over {128}}}}

... to

\infty

is equal to :

JEE Main 2020 · 9 Jan, Morning shift · Q5315

JEE Main 20209 Jan, Morning shiftMathematicsEasySequence and Series179× since 2002

The product

{2^{{1 \over 4}}}{.4^{{1 \over {16}}}}{.8^{{1 \over {48}}}}{.16^{{1 \over {128}}}}

... to

\infty

is equal to :