The potential energy of a particle changes with distance x from a fixed origin as V=(A x)/(x+B), where A and B are constant with appropriate dimensions. The dimensions of AB are _ _ _ _.

Units and Measurements: JEE Main 2026 Physics question

JEE Main 2026 · 6 Apr, Morning shift · Q27

JEE Main 20266 Apr, Morning shiftPhysicsEasyUnits and Measurements122× since 2002

The potential energy of a particle changes with distance

x

from a fixed origin as

V=\frac{A\sqrt x}{x+B}

, where

A

and

B

are constant with appropriate dimensions. The dimensions of

AB

are ________.