JEE Main 20199 Apr, Evening shiftPhysicsEasyKinematics177× since 2002The position vector of a particle changes with time according to the relation r→(t)=15t2i^+(4−20t2)j^\overrightarrow r (t) = 15{t^2}\widehat i + (4 - 20{t^2})\widehat jr(t)=15t2i+(4−20t2)j What is the magnitude of the acceleration at t = 1 ?AOption A. 50BOption B. 25COption C. 40DOption D. 100CheckSkip · show solution
