JEE Main 2008Annual, Paper 1MathematicsEasyCoordinate Geometry478× since 2002The point diametrically opposite to the point P(1,0)P(1, 0)P(1,0) on the circle x2+y2+2x+4y−3=0{x^2} + {y^2} + 2x + 4y - 3 = 0x2+y2+2x+4y−3=0 is :AOption A. (3,−4)(3, -4)(3,−4)BOption B. (−3,4)(-3, 4)(−3,4)COption C. (−3,−4)(-3, -4)(−3,−4)DOption D. (3,4)(3, 4)(3,4)CheckSkip · show solution
