JEE Main 202628 Jan, Evening shiftChemistryEasyChemical Thermodynamics84× since 2002The plot of log10K\log_{10}Klog10K vs 1T\frac{1}{T}T1 gives a straight line. The intercept and slope respectively are (where K is equilibrium constant).AOption A. −ΔH∘2.303R-\frac{\Delta H^\circ}{2.303R}−2.303RΔH∘, ΔS∘2.303R\frac{\Delta S^\circ}{2.303R}2.303RΔS∘BOption B. ΔS∘2.303R\frac{\Delta S^\circ}{2.303R}2.303RΔS∘, −ΔH∘2.303R-\frac{\Delta H^\circ}{2.303R}−2.303RΔH∘COption C. 2.303RΔH∘\frac{2.303R}{\Delta H^\circ}ΔH∘2.303R, 2.303RΔS∘\frac{2.303R}{\Delta S^\circ}ΔS∘2.303RDOption D. −ΔS∘R2.303-\frac{\Delta S^\circ R}{2.303}−2.303ΔS∘R, ΔH∘R2.303\frac{\Delta H^\circ R}{2.303}2.303ΔH∘RCheckSkip · show solution
