JEE Main 201912 Jan, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002The perpendicular distance from the origin to the plane containing the two lines, x+23=y−25=z+57{{x + 2} \over 3} = {{y - 2} \over 5} = {{z + 5} \over 7}3x+2=5y−2=7z+5 and x−11=y−44=z+47,{{x - 1} \over 1} = {{y - 4} \over 4} = {{z + 4} \over 7},1x−1=4y−4=7z+4, is :AOption A. 6116\sqrt {11}611BOption B. 116{{11} \over {\sqrt 6 }}611COption C. 11DOption D. 116\sqrt 66CheckSkip · show solution
