JEE Main 20249 Apr, Morning shiftMathematicsMediumIntegral Calculus369× since 2002The parabola y2=4xy^2=4 xy2=4x divides the area of the circle x2+y2=5x^2+y^2=5x2+y2=5 in two parts. The area of the smaller part is equal to :AOption A. 23+5sin−1(25)\frac{2}{3}+5 \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)32+5sin−1(52)BOption B. 23+5sin−1(25)\frac{2}{3}+\sqrt{5} \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)32+5sin−1(52)COption C. 13+5sin−1(25)\frac{1}{3}+5 \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)31+5sin−1(52)DOption D. 13+5sin−1(25)\frac{1}{3}+\sqrt{5} \sin ^{-1}\left(\frac{2}{\sqrt{5}}\right)31+5sin−1(52)CheckSkip · show solution
