JEE Main 2002Annual, Paper 1MathematicsEasyCoordinate Geometry478× since 2002The pair of lines represented by 3ax2+5xy+(a2−2)y2=03a{x^2} + 5xy + \left( {{a^2} - 2} \right){y^2} = 03ax2+5xy+(a2−2)y2=0 are perpendicular to each other for :AOption A. two values of aaaBOption B. ∀ a\forall \,a∀aCOption C. for one value of aaaDOption D. for no values of aaaCheckSkip · show solution