JEE Main 202120 Jul, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002The number of solutions of the equation log(x+1)(2x2+7x+5)+log(2x+5)(x+1)2−4=0{\log _{(x + 1)}}(2{x^2} + 7x + 5) + {\log _{(2x + 5)}}{(x + 1)^2} - 4 = 0log(x+1)(2x2+7x+5)+log(2x+5)(x+1)2−4=0, x > 0, is :Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
