The number of real roots of the equation e⁶ˣ - e⁴ˣ - 2e³ˣ - 12e²ˣ + eˣ + 1 = 0 is:

Complex Numbers and Quadratic Equations: JEE Main 2021 Mathematics question

JEE Main 2021 · 25 Jul, Morning shift · Q5045

JEE Main 202125 Jul, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002

The number of real roots of the equation

{e^{6x}} - {e^{4x}} - 2{e^{3x}} - 12{e^{2x}} + {e^x} + 1 = 0

is :

JEE Main 2021 · 25 Jul, Morning shift · Q5045

JEE Main 202125 Jul, Morning shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002

The number of real roots of the equation

{e^{6x}} - {e^{4x}} - 2{e^{3x}} - 12{e^{2x}} + {e^x} + 1 = 0

is :