JEE Main 202131 Aug, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002The number of real roots of the equation e4x+2e3x−ex−6=0{e^{4x}} + 2{e^{3x}} - {e^x} - 6 = 0e4x+2e3x−ex−6=0 is :AOption A. 2BOption B. 4COption C. 1DOption D. 0CheckSkip · show solution