The number of common tangents to the circles x² + y² - 4x - 6x - 12 = 0 and x² + y² + 6x + 18y + 26 = 0, is:

Coordinate Geometry: JEE Main 2015 Mathematics question

JEE Main 2015 · Session, Shift 1 · Q3091

JEE Main 2015Session, Shift 1MathematicsMediumCoordinate Geometry478× since 2002

The number of common tangents to the circles

{x^2} + {y^2} - 4x - 6x - 12 = 0

and

{x^2} + {y^2} + 6x + 18y + 26 = 0,

is :

JEE Main 2015 · Session, Shift 1 · Q3091

JEE Main 2015Session, Shift 1MathematicsMediumCoordinate Geometry478× since 2002

The number of common tangents to the circles

{x^2} + {y^2} - 4x - 6x - 12 = 0

and

{x^2} + {y^2} + 6x + 18y + 26 = 0,

is :