The normal to the curve, x² + 2xy - 3y² = 0, at (1,1)

(B) meets the curve again in the fourth quadrant.

(A) meets the curve again in the third quadrant.

(C) does not meet the curve again.

(D) meets the curve again in the second quadrant.

Limit, Continuity and Differentiability: JEE Main 2015 Mathematics question

JEE Main 2015 · Session, Shift 1 · Q2758

JEE Main 2015Session, Shift 1MathematicsEasyLimit, Continuity and Differentiability420× since 2002

The normal to the curve,

{x^2} + 2xy - 3{y^2} = 0

, at

(1,1)

JEE Main 2015 · Session, Shift 1 · Q2758

JEE Main 2015Session, Shift 1MathematicsEasyLimit, Continuity and Differentiability420× since 2002

The normal to the curve,

{x^2} + 2xy - 3{y^2} = 0

, at

(1,1)