The minimum value of f(x) = a^(aˣ) + a^(1 - aˣ), where a, x R and a > 0, is equal to:

Sequence and Series: JEE Main 2021 Mathematics question

JEE Main 2021 · 25 Feb, Evening shift · Q5180

JEE Main 202125 Feb, Evening shiftMathematicsEasySequence and Series179× since 2002

The minimum value of

f(x) = {a^{{a^x}}} + {a^{1 - {a^x}}}

, where a,

x \in R

and a > 0, is equal to :

JEE Main 2021 · 25 Feb, Evening shift · Q5180

JEE Main 202125 Feb, Evening shiftMathematicsEasySequence and Series179× since 2002

The minimum value of

f(x) = {a^{{a^x}}} + {a^{1 - {a^x}}}

, where a,

x \in R

and a > 0, is equal to :