JEE Main 20169 Apr, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002The minimum distance of a point on the curve y = x²−4 from the origin is :AOption A. 192{{\sqrt {19} } \over 2}219BOption B. 152\sqrt {{{15} \over 2}}215COption C. 152{{\sqrt {15} } \over 2}215DOption D. 192\sqrt {{{19} \over 2}}219CheckSkip · show solution
