The mean free path of a molecule of diameter 5 × 10⁻¹⁰ m at the temperature 41°C and pressure 1.38 × 10⁵ Pa, is given as _ _ _ _ m. (Given k B = 1.38 × 10⁻²³ J/K).

Kinetic Theory of Gases: JEE Main 2026 Physics question

JEE Main 2026 · 28 Jan, Evening shift · Q40

JEE Main 202628 Jan, Evening shiftPhysicsEasyKinetic Theory of Gases52× since 2002

The mean free path of a molecule of diameter

5 \times 10^{-10}

m at the temperature 41 °C and pressure

1.38 \times 10^5

Pa, is given as ________ m. (Given

k_B = 1.38 \times 10^{-23}

J/K).