JEE Main 2003Annual, Paper 1MathematicsMediumStatistics and Probability258× since 2002The mean and variance of a random variable XXX having binomial distribution are 444 and 222 respectively, then P(X=1)P(X=1)P(X=1) is :AOption A. 14{1 \over 4}41BOption B. 132{1 \over 32}321COption C. 116{1 \over 16}161DOption D. 18{1 \over 8}81CheckSkip · show solution
