JEE Main 202226 Jul, Morning shiftMathematicsMediumStatistics and Probability258× since 2002The mean and variance of a binomial distribution are α\alphaα and α3\frac{\alpha}{3}3α respectively. If P(X=1)=4243\mathrm{P}(X=1)=\frac{4}{243}P(X=1)=2434, then P(X=4\mathrm{P}(X=4P(X=4 or 5))) is equal to :AOption A. 59\frac{5}{9}95BOption B. 6481\frac{64}{81}8164COption C. 1627\frac{16}{27}2716DOption D. 145243\frac{145}{243}243145CheckSkip · show solution
