JEE Main 202126 Feb, Morning shiftMathematicsMediumBinomial Theorem and Its Simple Applications131× since 2002The maximum value of the term independent of 't' in the expansion of (tx15+(1−x)110t)10{\left( {t{x^{{1 \over 5}}} + {{{{(1 - x)}^{{1 \over {10}}}}} \over t}} \right)^{10}}(tx51+t(1−x)101)10 where x∈\in∈(0, 1) is :AOption A. 10!3(5!)2{{10!} \over {\sqrt 3 {{(5!)}^2}}}3(5!)210!BOption B. 2.10!33(5!)2{{2.10!} \over {3\sqrt 3 {{(5!)}^2}}}33(5!)22.10!COption C. 10!3(5!)2{{10!} \over {3{{(5!)}^2}}}3(5!)210!DOption D. 2.10!3(5!)2{{2.10!} \over {3{{(5!)}^2}}}3(5!)22.10!CheckSkip · show solution
