JEE Main 2006Annual, Paper 1MathematicsMediumCoordinate Geometry478× since 2002The locus of the vertices of the family of parabolas y=a3x23+a2x2−2ay = {{{a^3}{x^2}} \over 3} + {{{a^2}x} \over 2} - 2ay=3a3x2+2a2x−2a is :AOption A. xy=10564xy = {{105} \over {64}}xy=64105BOption B. xy=34xy = {{3} \over {4}}xy=43COption C. xy=3516xy = {{35} \over {16}}xy=1635DOption D. xy=64105xy = {{64} \over {105}}xy=10564CheckSkip · show solution
