JEE Main 201816 Apr, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002The locus of the point of intersection of the lines, 2x−y+42k=0\sqrt 2 x - y + 4\sqrt 2 k = 02x−y+42k=0 and 2k x+k y−42=0\sqrt 2 k\,x + k\,y - 4\sqrt 2 = 02kx+ky−42=0 (k is any non-zero real parameter), is :AOption A. an ellipse whose eccentricity is 13.{1 \over {\sqrt 3 }}.31.BOption B. an ellipse with length of its major axis 82.8\sqrt 2 .82.COption C. a hyperbola whose eccentricity is 3.\sqrt 3 .3.DOption D. a hyperbola with length of its transverse axis 82.8\sqrt 2 .82.CheckSkip · show solution
