JEE Main 202116 Mar, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002The locus of the midpoints of the chord of the circle, x² + y² = 25 which is tangent to the hyperbola, x29−y216=1{{{x^2}} \over 9} - {{{y^2}} \over {16}} = 19x2−16y2=1 is :AOption A. (x² + y²)² −-− 9x² + 16y² = 0BOption B. (x² + y²)² −-− 9x² + 144y² = 0COption C. (x² + y²)² −-− 16x² + 9y² = 0DOption D. (x² + y²)² −-− 9x² −-− 16y² = 0CheckSkip · show solution
