JEE Main 2003Annual, Paper 1MathematicsEasyCoordinate Geometry478× since 2002The lines 2x - 3y = 5 and 3x - 4y = 7 are diameters of a circle having area as 154 sq. units. Then the equation of the circle is :AOption A. x2 + y2− 2x + 2y = 62{x^2}\, + \,{y^2} - \,2x\, + \,2y\,\, = \,62x2+y2−2x+2y=62BOption B. x2 + y2+ 2x − 2y = 62{x^2}\, + \,{y^2} + \,2x\, - \,2y\,\, = \,62x2+y2+2x−2y=62COption C. x2 + y2+ 2x − 2y = 47{x^2}\, + \,{y^2} + \,2x\, - \,2y\,\, = \,47x2+y2+2x−2y=47DOption D. x2 + y2− 2x + 2y = 47{x^2}\, + \,{y^2} - \,2x\, + \,2y\,\, = \,47x2+y2−2x+2y=47CheckSkip · show solution
